While Humpy is among the seeded players, Harika qualified for the event through the playoff qualifiers
This picture has been used for representation purpose
India's International Master R Vaishali has qualified for the FIDE Chess.com Women's Speed Chess Championship Grand Prix which begins later on Wednesday. The Chennai player, sister of young chess prodigy R Praggnanandhaa, joins India's top two players Koneru Humpy and D Harika in the tournament. Hou Yifan and world champion Ju Wenju, both Chinese, will also be part of the event. While Humpy is among the seeded players, Harika qualified for the event through the playoff qualifiers.
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Vaishali, the Asian Blitz Championship winner in 2017, will take on Antoaneta Stefanova of Bulgaria while Humpy meets Le Thao Nguyen Pham (Vietnam).
Vaishali said she was very happy to qualify for the GP from the fifth qualifier. "I am happy to have been able to qualify for the GP. I participated in the first four qualifiers too and managed to do so from the fifth (qualifier)," she told PTI. She rated her win against Alina Kashlinskaya in the qualifying event as her best, saying it gave her confidence.
"The win against Alina Alina Kashlinskaya was a good one and it gave me a lot of confidence," she added. Speaking about Vaishali qualifying for the GP, her coach R B Ramesh praised the performance and said she was good in blitz. "It is a good thing. She is generally very good in blitz and had won the Asian Blitz Championship in 2017 in China."
The Grand Prix will consist of four legs, with a total of 21 participants. Each of the 21 players participates in three out of four Grand Prix legs. Each GP is a 16-player knockout event and the first one is from June 24 to 28. In each Grand Prix leg, every player scores cumulative grand prix points according to the position in the final standings. The two players who score the highest number of cumulative grand prix points in all three legs qualify for the Super Final to be held on July 20.
Each one of the Grand Prix legs has a total prize fund of USD 10,300 with USD 3,000 going to the winner.
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