Updated On: 07 September, 2020 07:22 AM IST | Dubai | PTI
After the tournament-opener in the capital city, Dubai will host its first game the next day when Delhi Capitals take on Kings XI Punjab followed by the third match on Monday between Sunrisers Hyderabad and Royal Challengers Bangalore

MI's pace ace Jasprit Bumrah and skipper Rohit Sharma during a training session in the UAE recently. Pic/Mumbaiindians.com
Ending days of anxious wait, the BCCI on Sunday released the schedule for the upcoming IPL, and in keeping with tradition, defending champions Mumbai Indians will take on runners-up Chennai Super Kings in the opener in Abu Dhabi on September 19. Moved out of India due to a surge in COVID-19 cases, the upcoming edition of the world's biggest T20 league will be held in the three venues of Dubai, Abu Dhabi and Sharjah in the UAE. After the tournament-opener in the capital city, Dubai will host its first game the next day when Delhi Capitals take on Kings XI Punjab followed by the third match on Monday between Sunrisers Hyderabad and Royal Challengers Bangalore.
The action will then shift to Sharjah on September 22 when Rajasthan Royals will host Chennai Super Kings. There will be 10 double headers, with the first match starting at 3:30pm IST and the second 7:30pm, according to a BCCI release. In all, 24 matches will be held in Dubai, 20 in Abu Dhabi and 12 in Sharjah. Venues for the playoffs and the IPL 2020 final will be announced later. The final is slated for November 10. The upcoming 53-day edition is by far the longest in the history of the league. The schedule was expected to be out in the last week of August but the announcement was delayed after 13 personnel of the Chennai Super Kings (CSK) camp tested positive for the dreaded virus. Also, due to different quarantine rules in Dubai and Abu Dhabi, IPL's operations team took time to finalise the schedule. As per IPL rules, the defending champions and the last year's runner-up face off in the tournament opener.