It has been a rollercoaster ride for SRH who won five games in a row before losing the next five. SRH, if they win their two remaining games including the one against MI, will jump to 14 points and then be left hoping that the other results go their way to have an outside chance of making the play-offs
Kane Williamson
Their play-off chances hanging by a thread, Sunrisers Hyderabad will need to snap their five-match losing streak when they take on an already eliminated Mumbai Indians in the IPL at the Wankhede Stadium on Tuesday.
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It has been a rollercoaster ride for SRH who won five games in a row before losing the next five. SRH, if they win their two remaining games including the one against MI, will jump to 14 points and then be left hoping that the other results go their way to have an outside chance of making the play-offs.
But a loss against Mumbai at the Wankhede stadium will surely eliminate them, as there are already seven teams now with 12 or more points.
Hyderabad will need to put up a much improved show with the bat.
Skipper Kane Williamson is enduring a wretched run in this season and the Kiwi has collected just 208 runs from 12 games at an average of 18.92. He needs to find his mojo.
Head coach Tom Moody defended the move to open with an out-of-form Williamson and the New Zealander will need to prove his coach right.
His opening partner Abhishek Sharma, who chipped in with a 43 in the last game, needs to convert the starts to big scores. But the duo would have their task cut out against a formidable Mumbai attack on a track that helps pacers.
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